8)

f(t)=0,4t32tdx=0,1t4t2+cF(a)=0,1a4a2+cF(3)=0,124+42c3=0,1616+c3+0,1616=c13,16=cF(a)=0,1t4t213,16
2a2x+12dx=39[x2+12x]2a=39(a2+12a)((2)2+12(2))=39(a212a)+28=39(a212a)pq:p2±p22q=122±1222=6±6=[0,12]28=39a=[0,12]