a)

${\int }_{-1}^0(e^{2x}+2)dx={[\frac{1}{2}{e}^{2x}+2x]}_{-1}^0=\frac{1}{2}-\frac{1}{2e^2}+2=\frac{5}{2}-\frac{1}{2e^2}$

b)

${\int }_1^3(23-7\ast e^{3,53})d3={[3^2-7\ast \frac{7}{2}\ast e^{3,53}]}_1^3$
$=3^2-2\ast e^{3,5\ast 3}-(1^2-2\ast e^{3,5\ast 1})=9-2\ast e^{10,5}-(1-2\ast e^{3.5})$